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4.9x^2-24.8x+15=0
a = 4.9; b = -24.8; c = +15;
Δ = b2-4ac
Δ = -24.82-4·4.9·15
Δ = 321.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.8)-\sqrt{321.04}}{2*4.9}=\frac{24.8-\sqrt{321.04}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.8)+\sqrt{321.04}}{2*4.9}=\frac{24.8+\sqrt{321.04}}{9.8} $
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